数据库课件总结:DataBase-Chapter-Two-Outline.docx
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1、DataBase Chapter Two OutlineThe set of allowed values for each attribute is called the domain of the attributer(R) is a relation on the relation schema RExample:customer (Customer_schema)About Key:K is a superkey of R if values for K are sufficient to identify a unique tuple of each possible relatio
2、n r(R)K is a candidate key if K is minimal (最小超码)Primary Key :被数据库设计者选中的用来在同一关系中区分不同元组的候选码。Relational AlgebraProcedural language Six basic operators select: o project: fl union: u set difference:- Cartesian product: x rename: pThe operators take one or two relations as inputs and produce a new relat
3、ion as a result.Select Operation Notation: (Jp(r) p is called the selection predicate Defined as: a-p(r) = t t e rand p(t)Where p is a formula in propositional calculus consisting of terms connected by : a (and), v (or), -i (not)Each term is one of: op or where op is one of: =, w, , . . Project Oper
4、ation. Notation:where Ai, A2 are attribute names and r is a relation name.Union OperationNotation: 2 sDefined as:r us = f | t e ror t e s For r u s to be valid.1. r, s must have the same arity (same number of attributes)2. The attribute domains must be compatible (example: 2nd column of r deals with
5、 the same type of values as does the 2nd column of s)Set Difference OperationNotation r-sDefined as:r-s = t | t e rand t g sSet differences must be taken between compatible relations.r and s must have the same arityattribute domains of r and s must be compatibleCartesian-Product OperationNotation r
6、x sDefined as:rxs = t q | ter and q e sAssume that attributes of r(R) and s(S) are disjoint. (That is, /? n S = 0.If attributes of r(R) and s(S) are not disjoint, then renaming must be used.Rename OperationAllows us to name, and therefore to refer to, the results of relational-algebra expressions. A
7、llows us to refer to a relation by more than one name.Example:px(E)returns the expression E under the name XIf a relational-algebra expression E has arity n, thenPx(Al9A2returns the result of expression E under the name X, and with theattributes renamed to Ai, 2,An.Additional OperationsSet-Intersect
8、ion OperationNotation: rnsDefined as:r s = t t e rand t e sAssume:r, s have the same arity attributes of r and s are compatibleNote: rns = r-(r-s)Natural-Join OperationNotation: rtxsLet r and s be relations on schemas R and S respectively.Then, r rx s is a relation on schema R oS obtained as follows
9、:Consider each pair of tuples tr from r and ts from s.If tr and ts have the same value on each of the attributes in R c S, add a tuple t to the result, wheret has the same value as tr on r t has the same value as ts on s0 -Join Operationrixes= o o(rxs)Division OperationNotation:Suited to queries tha
10、t include the phrase for all.Let r and s be relations on schemas R and 5 respectively whereR =依17 /Am / Bl / Bn)S = (Bi,Bn)The result of r-r s is a relation on schemaR - S = (4,., Am)rs = t t e R-s(r) / u e s (tu e r)Where tu means the concatenation of tuples t and u to produce a single tupler-r s =
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