chemical-reaction-engineering-3ed-edition作者-octave-Levenspiel-课后习题答案.doc
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1、 Corresponding Solutions for Chemical Reaction EngineeringCHAPTER 1 OVERVIEW OF CHEMICAL REACTION ENGINEERING1CHAPTER 2 KINETICS OF HOMOGENEOUS REACTIONS3CHAPTER 3 INTERPRETATION OF BATCH REACTOR DATA7CHAPTER 4 INTRODUCTION TO REACTOR DESIGN19CHAPTER 5 IDEAL REACTOR FOR A SINGLE REACTOR22CHAPTER 6 D
2、ESIGN FOR SINGLE REACTIONS26CHAPTER 10 CHOOSING THE RIGHT KIND OF REACTOR32CHAPTER 11 BASICS OF NON-IDEAL FLOW34CHAPTER 18 SOLID CATALYZED REACTIONS43Chapter 1 Overview of Chemical Reaction Engineering1.1 Municipal waste water treatment plant. Consider a municipal water treatment plant for a small c
3、ommunity (Fig.P1.1). Waste water, 32000 m3/day, flows through the treatment plant with a mean residence time of 8 hr, air is bubbled through the tanks, and microbes in the tank attack and break down the organic material (organic waste) +O2 CO2 + H2O A typical entering feed has a BOD (biological oxyg
4、en demand) of 200 mg O2/liter, while the effluent has a megligible BOD. Find the rate of reaction, or decrease in BOD in the treatment tanks. Waste water32,000 m3/dayWaste waterTreatment plant Clean water 32,000 m3/day200 mg O2needed/literMean residencetime =8 hr Zero O2 neededFigure P1.1Solution:1.
5、2 Coal burning electrical power station. Large central power stations (about 1000 MW electrical) using fluiding bed combustors may be built some day (see Fig.P1.2). These giants would be fed 240 tons of coal/hr (90% C, 10%H2), 50% of which would burn within the battery of primary fluidized beds, the
6、 other 50% elsewhere in the system. One suggested design would use a battery of 10 fluidized beds, each 20 m long, 4 m wide, and containing solids to a depth of 1 m. Find the rate of reaction within the beds, based on the oxygen used.Solution:Chapter 2 Kinetics of Homogeneous Reactions2.1 A reaction
7、 has the stoichiometric equation A + B =2R . What is the order of reaction?Solution: Because we dont know whether it is an elementary reaction or not, we cant tell the index of the reaction.2.2 Given the reaction 2NO2 + 1/2 O2 = N2O5 , what is the relation between the rates of formation and disappea
8、rance of the three reaction components?Solution: 2.3 A reaction with stoichiometric equation 0.5 A + B = R +0.5 S has the following rate expression-rA = 2 C0.5 ACB What is the rate expression for this reaction if the stoichiometric equation is written as A + 2B = 2R + SSolution: No change. The stoic
9、hiometric equation cant effect the rate equation, so it doesnt change.2.4 For the enzyme-substrate reaction of Example 2, the rate of disappearance of substrate is given by-rA = , mol/m3s What are the units of the two constants?Solution: 2.5 For the complex reaction with stoichiometry A + 3B 2R + S
10、and with second-order rate expression -rA = k1AB are the reaction rates related as follows: rA= rB= rR? If the rates are not so related, then how are they related? Please account for the sings , + or - .Solution: 2.6 A certain reaction has a rate given by -rA = 0.005 C2 A , mol/cm3min If the concent
11、ration is to be expressed in mol/liter and time in hours, what would be the value and units of the rate constant?Solution:2.7 For a gas reaction at 400 K the rate is reported as - = 3.66 p2 A, atm/hr (a) What are the units of the rate constant? (b) What is the value of the rate constant for this rea
12、ction if the rate equation is expressed as -rA = - = k C2 A , mol/m3sSolution:(a) The unit of the rate constant is (b)Because its a gas reaction occuring at the fined terperatuse, so V=constant, and T=constant, so the equation can be reduced to So we can get that the value of 2.9 The pyrolysis of et
13、hane proceeds with an activation energy of about 300 kJ/mol. How much faster the decomposition at 650 than at 500?Solution:2.11 In the mid-nineteenth century the entomologist Henri Fabre noted that French ants (garden variety) busily bustled about their business on hot days but were rather sluggish
14、on cool days. Checking his results with Oregon ants, I find Running speed, m/hr150160230295370Temperature, 1316222428 What activation energy represents this change in bustliness?Solution:Suppose , so intercept150160230295370-3.1780-3.1135-2.7506-2.5017-2.275213162224283.49473.45843.38813.36533.3206-
15、y = -5147.9 x + 15.686Also , intercept = 15.686 ,Chapter 3 Interpretation of Batch Reactor Data3.1 If -rA = - (dCA/dt) =0.2 mol/litersec when CA = 1 mol/liter, what is the rate of reaction when CA = 10 mol/liter?Note: the order of reaction is not known.Solution: Information is not enough, so we cant
16、 answer this kind of question.3.2 Liquid a sedomposes by first-order kinetics, and in a batch reactor 50% of A is converted in a 5-minute run. How much longer would it take to reach 75% conversion?Solution: Because the decomposition of A is a 1st-order reaction, so we can express the rate equation a
17、s:We know that for 1st-order reaction, , , So equ(1) equ(2)So 3.3 Repeat the previous problem for second-order kinetics.Solution: We know that for 2nd-order reaction, ,So we have two equations as follow:, equ(1), equ(2)So , 3.4 A 10-minute experimental run shows that 75% of liquid reactant is conver
18、ted to product by a -order rate. What would be the fraction converted in a half-hour run?Solution:In a order reaction: ,After integration, we can get: ,So we have two equations as follow:, equ(1), equ(2)Combining these two equations, we can get:, but this means , which is impossible, so we can concl
19、ude that less than half hours, all the reactant is consumed up. So the fraction converted .3.5 In a hmogeneous isothermal liquid polymerization, 20% of the monomer disappears in 34 minutes for initial monomer concentration of 0.04 and also for 0.8 mol/liter. What rate equation represents the disappe
20、arance of the monomer?Solution: The rate of reactant is independent of the initial concentration of monomers, so we know the order of reaction is first-order,And 3.6 After 8 minutes in a batch reactor, reactant (CA0 = 1 mol/liter) is 80% converted; after 18 minutes, conversion is 90%. Find a rate eq
21、uation to represent this reaction.Solution:In 1st order reaction, , dissatisfied.In 2nd order reaction, , satisfied.According to the information, the reaction is a 2nd-order reaction.3.7 nake-Eyes Magoo is a man of habit. For instance, his Friday evenings are all alikeinto the joint with his weeks s
22、alary of 180, steady gambling at “2-up” for two hours, then home to his family leaving 45 behind. Snake Eyess betting pattern is predictable. He always bets in amounts proportional to his cash at hand, and his losses are also predictableat a rate proportional to his cash at hand. This week Snake-Eye
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